std::chrono::year_month_weekday_last:: operator+=, std::chrono::year_month_weekday_last:: operator-=

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< cpp ‎ | chrono ‎ | year month weekday last

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constexpr std:: chrono :: year_month_weekday_last & operator + = ( const std:: chrono :: years & dy ) const noexcept ;	(1)	(C++20以降)
constexpr std:: chrono :: year_month_weekday_last & operator + = ( const std:: chrono :: months & dm ) const noexcept ;	(2)	(C++20以降)
constexpr std:: chrono :: year_month_weekday_last & operator - = ( const std:: chrono :: years & dy ) const noexcept ;	(3)	(C++20以降)
constexpr std:: chrono :: year_month_weekday_last & operator - = ( const std:: chrono :: months & dm ) const noexcept ;	(4)	(C++20以降)

この時間点 * this を、期間 dy または dm によって変更します。

1) 次と等価: * this = * this + dy ; .

2) 次と同等： * this = * this + dm ; 。

3) 次と等価： * this = * this - dy ; 。

4) 次と等価： * this = * this - dm ; 。

期間が std::chrono::years と std::chrono::months の両方に変換可能な場合、呼び出しが曖昧になる可能性があるときは years のオーバーロード (1,3) が優先されます。

例

このコードを実行

#include <chrono>
#include <iostream>
using namespace std::chrono;
int main()
{
    auto ymwdl{August/Friday[last]/2022};
    std::cout << year_month_day{ymwdl} << '\n';
    ymwdl += months(2);
    std::cout << year_month_day{ymwdl} << '\n';
    ymwdl -= years(1); 
    std::cout << year_month_day{ymwdl} << '\n';
}

出力:

2022-08-26
2022-10-28
2021-10-29

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Member functions
year_month_weekday_last::year_month_weekday_last
year_month_weekday_last::operator+= year_month_weekday_last::operator-=
year_month_weekday_last::year year_month_weekday_last::month year_month_weekday_last::weekday year_month_weekday_last::weekday_last
year_month_weekday_last::operator sys_days year_month_weekday_last::operator local_days
year_month_weekday_last::ok
Nonmember functions
operator==
operator+ operator-
operator<<
Helper classes
formatter <std::chrono::year_month_weekday_last>
hash <std::chrono::year_month_weekday_last> (C++26)

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std::chrono::year_month_weekday_last:: operator+=, std::chrono::year_month_weekday_last:: operator-=

例

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